25x^2-28x-132=0

Solution for 25x^2-28x-132=0 equation:

25x^2-28x-132=0

a = 25; b = -28; c = -132;
Δ = b2-4ac
Δ = -282-4·25·(-132)
Δ = 13984
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{13984}=\sqrt{16*874}=\sqrt{16}*\sqrt{874}=4\sqrt{874}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-4\sqrt{874}}{2*25}=\frac{28-4\sqrt{874}}{50}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+4\sqrt{874}}{2*25}=\frac{28+4\sqrt{874}}{50}
$